WebOct 10, 2011 · 2,436. Oct 10, 2011. #4. TBayBoy said: I was leaning in that direction, but maybe the lack of vcc was spooking me. So Ve is 0, vb is 0.7 vrb is 3.96V and Vc = … WebVe = Vb - 0.7V. Once you know Ve you know the emitter current . Ie= Ve/Re, and since the base current is assumed to be zero, you can find . Vc = Vcc - Ie * Rc. That is valid if \$\frac{R1R2}{R1+R2}\$ << \$\beta Re\$ If you want more accuracy you have to solve this circuit: simulate this circuit – Schematic created using CircuitLab. where
Chapter 8, Problem 1. - University of Nevada, Las Vegas
Web= 3−0.7 1 = 2.3mA. If we assume active mode then IC = αIE = 30 30+1 × 2.3 = 2.2mA. Then VC = VCC + ICRC = −3 + 2.2 = −0.8V, and active mode is verified. Finally, IB = IC β = 2. 30 = 73,µA. (c) VB = 3V, and the transistor is on, so VE = VB + VEB = 3 + 0.7 = 3.7V. Then IE = VEE−VE RE = 9−3.7 1.1 = 4.8mA. Assuming active mode we get ... WebIf Ic and β are known, then Ie can be calculated by the formula: Example. If Ic= 2.97ma and β=99, then Ie is calculated out to be: 4th Way to Calculate Emitter Current I e. Using Known Values If Ib and Ic are known, Ie can … tey young
Finding the Base-Emitter Voltage in an NPN Transistor
WebEngineering Electrical Engineering Determine VCE and Ic in the stiff voltage-divider biased transistor circuit of Figur if Bpc = 100. FIGURE 5-10 Vcc +10 V 10 k Re 1.0 kN R2 5.6 k RE 560 N tion The base voltage is R2 5.6 kN 10 V = 3.59 V VB = R+R Vcc = 15.6 kN So, VE = VB - VBE = 3.59 V – 0.7 V = 2.89 V and VE 2.89 V = 5.16 mA %3D %3D RE 560 ... WebFigure 6 . 14. Determine whether the transistor in Figure 7 is biased in cutoff, saturation or the linear region. Keep in mind that . I C = β DC I B is valid only in the linear region . Figure 7 . 15. Calculate all transistor terminal voltages with respect to groundin Figure 8. Do not neglect the input resistance at the base or V BE. VCC 18 V http://www.learningaboutelectronics.com/Articles/How-to-calculate-the-collector-current-ic-of-a-transistor teyyo_off