Weba − b − 4 a 2 + 4 b 2 = (a − b) − 4 (a 2 − b 2) = (a − b) − 4 (a + b) (a − b) = (a − b) (1 − 4 (a + b)) = (a − b) (1 − 4 a − 4 b) Webfactorise a^2+b^2-2(ab-ac+bc). factorise 4a^2-9b^2-(2a-3b). factorise a-b-a2+b2. factorise 108a^2-3(b-c)^2. factorise 25x^2-10x+1-36y^2#polynomialsbyavisir #...

Solve 4a^2-9b^2-16c^2+24bc Microsoft Math Solver

WebPopular Problems. Algebra. Factor a^2+4a+4-b^2. a2 + 4a + 4 − b2 a 2 + 4 a + 4 - b 2. Factor using the perfect square rule. Tap for more steps... (a+2)2 −b2 ( a + 2) 2 - b 2. … WebCheck that the middle term is two times the product of the numbers being squared in the first term and third term. 4a = 2⋅a ⋅2 4 a = 2 ⋅ a ⋅ 2 Rewrite the polynomial. a2 − 2⋅a⋅2+22 a 2 - … primefaces with jsr286

Factorize: 4a^2 + b^2 + 4ab + 8a + 4b + 4 - Brainly.in

WebClick here👆to get an answer to your question ️ Factorise: 4a^2 + b^2 + 25c^2 - 4ab - 10bc + 20ca. Solve Study Textbooks Guides. Join / Login. Question . Factorise: 4 a 2 + b 2 + 2 5 c 2 ... Solution. Verified by Toppr. Correct option is C) 4 a 2 + b 2 + 2 5 c 2 ... WebMay 2, 2024 · Factorise: 16a 2 -144. factorisation; class-8; Share It On Facebook Twitter Email. 1 Answer +1 vote . answered May 2 ... selected May 2, 2024 by Nidhi01 . Best answer. 16a 2 -144 can be written as (4a) 2 – (12) 2. By using the formula a 2 – b 2 = (a+b) (a-b) Now solving for the above equation (4a) 2 – (12) 2 = (4a+12) (4a-12) = 4(a+3) 4(a ... WebCorrect option is B) We have, 4a 2=2×2×a×a, 4ab=2×2×a×b and, 4ca=2×2×c×a The three terms have 2, 2 and a as common facotrs −4a 2+4ab−4ca=−(2×2×a×a)+(2×2×a×b)−(2×2×c×a) =2×2×a×(−a+b−c) =4a(−a+b−c) =−4a(a−b+c) Was this answer helpful? 0 0 Similar questions Factorise: 4a+12b Easy … primefaces wcag